3 ms·
> you might not want to multiply N and M with Y dapr nodes That would be bad, but my understanding of the "sidecar" is that there would be M dapper nodes, each
by SideburnsOfDoom 7y ago
> you might not want to multiply N and M with Y dapr nodes
That would be bad, but my understanding of the "sidecar" is that there would be M dapper nodes, each attached to a main consumer in a container. (and probably add N dapper nodes as well, if the N senders are also containerised and managed this way)