4 ms·
I wouldn't describe this as "no-one knows" the type of char + char. I know what the type of char + char is. I know that it's either int or unsigned int, depen
by _kst_ 7y ago
I wouldn't describe this as "no-one knows" the type of char + char.
I know what the type of char + char is. I know that it's either int or unsigned int, depending on the ranges of values supported by types char and int. I know what it is for any given implementation. And I know that it's int, not unsigned int, for every implementation I've ever used or am likely to use.
Implementation-defined features are not some unsolvable mystery. They're just implementation-defined.
- BearOso 7y agoAnd we can count 99.999% of used implementations on one hand. If you’re on a strange platform, there’s a reason for that, and chances are you’re uniquely aware of any differences or will be writing assembly.