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No, it would not free it. It takes a reference to the pointer and does nothing.
by SamReidHughes 7y ago
No, it would not free it. It takes a reference to the pointer and does nothing.
- dkersten 7y agounique_ptr disposes of the object its holding when it goes out of scope unless passed to another unique_ptr or ownership is explicitly released. Presumably klipt would std::move the unique_ptr, hence the universal reference (which seems unnecessary, just pass it by value). Am I missing something? Does it not work with std::move?
- Rusky 7y agoYes, you're missing that the type `T&&` is a reference, not a value, and so does not run the object's destructor when it goes out of scope.
- dkersten 7y agoSorry, I edited right after hitting reply to clarify that I'm assuming the intention was to std::move the unique_ptr in, since it was T&& and not T&. Would that still not work?