3 ms·
You could argue that ROT13 accidentally has second-preimage resistance because given m, you won't be able to find n≠m where ROT13(n)=ROT13(m). :-)
by schoen 7y ago
You could argue that ROT13 accidentally has second-preimage resistance because given m, you won't be able to find n≠m where ROT13(n)=ROT13(m). :-)