3 ms·
Completely fake. Hilariously so. Seriously, do some calculations on the joule requirements to do this. Simple comparison: think about how a 1000W microwave t
by timcederman 18y ago
Completely fake. Hilariously so. Seriously, do some calculations on the joule requirements to do this. Simple comparison: think about how a 1000W microwave takes 60 seconds to pop popcorn.
- noonespecial 18y agoDon't mind if I do! A popcorn kernel has about 1/10 gram of water in it. We have to boil this water to pop the kernel. How much power do we need to turn this much water to steam in the time in the video (about 10 seconds)? First heat the water from room temp (21C) to 100C: dT * .1g -> 79 * .1 = 7.9 calories = 33.0536 joules Now add to that the latent heat for boiling to get our 100 degree water to steam (2260j/g) 2260*.1 = 226J Add it together and we need about 226 + 33 = 259 Joules of energy to pop a kernel. So how much power is that? 1 Watt is of course energy expended at 1 joule per second. A 10 second pop of a kernel would need a steady 259/10 = 25.9 watts of continuous power to be fed directly into the kernel for 10 seconds to make it pop! Do you think your cell phone transmits at 26 watts? (Much more than that actually since there is no way even a good fraction of all transmitted power would make it into the kernel). Even with 4 phones, each would have to transmit at at least 6.5 watts, have perfectly directional antennas, pointed directly at a single kernel, for ten seconds. Checking with the FCC filing for my moto shows a max transmission power allowed at 1 watt. Typical being 0.2 watts. I call bullshit. Don't believe the math? Go to the medicine cabinet and get a thermometer, put it in a little bit of water at the bottom of a glass and see if there is anything you can do with your phone to heat the water even one degree. You'd have more luck shaking it vigorously.
- timcederman 18y agoThanks for filling in for my laziness :)