2 ms·
Again, it may very well be a vanilla TLS, but then you have a bit of code in some obscure corner that repoints random() to an alternative weaker implementation
by huhtenberg 7y ago
Again, it may very well be a vanilla TLS, but then you have a bit of code in some obscure corner that repoints random() to an alternative weaker implementation when some conditions are met, including, for example, not being run under a debugger and not having certain popular functions trampolined.
Good luck finding even this without a fine comb. And that's us just getting started with code flow obfuscation.
No source = no trust. It's as simple as that.