3 ms·
Remove the leading 3 and the trailing term of 1/4 increasing in power. You are left with this (in the 4th line): 1 3 5 1 - - - - 2 4 6 7 The pattern I see
by joeyrideout 7y ago
Remove the leading 3 and the trailing term of 1/4 increasing in power.
You are left with this (in the 4th line):
1 3 5 1
- - - -
2 4 6 7
The pattern I see is that, starting from the top left and reading numerator, denominator, numerator, denominator and so on gives: 1 2 3 4 5 6 7 if you ignore the last numerator.
I may have it wrong, but that looks like the pattern.
- mef51 7y ago4th step is 1357/2468
- joeyrideout 7y agoIs that simplified? I'm just going off of this image: http://ajennings.net/blog/images/formula.png http://ajennings.net/blog/images/formula.png
- mef51 7y agome too, the pattern to me is odds on the numerator and evens in the denominator, and the second fraction goes 1/3, 1/5, 1/7, 1/9... i think we're saying the same thing i misunderstood your comment. 1357/2468 is the first fraction of the NEXT line that isnt in the image
- joeyrideout 7y agoAha, yes, I edited my post now to say 4th line not 4th step. Leave it to HN to get an off-by-one error :)