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Thank you very much CrazyStat. I was convinced that "x-bar and s are independent for data coming from a Normal distribution". So the conclusion is for my exampl
by keyboardman 7y ago
Thank you very much CrazyStat. I was convinced that "x-bar and s are independent for data coming from a Normal distribution". So the conclusion is for my example, p(x|mu) is normal distribution, p(x-bar|mu), after derivation, is also normal distribution. If p(x|mu) comes from some other distributions, p(x-bar|mu), however, might not be normal.
Thanks for providing the proof, and I will only be convinced by the proof :) Will update the post shortly. Thanks for the great conversation and suggestions.