4 ms·(x^0) = (1) makes sense because lim{y -> 0} (x^y) = (1). E.g. (10^0.001) = (1.00230524...)by Double_Cast 7y ago(x^0) = (1) makes sense because lim{y -> 0} (x^y) = (1). E.g. (10^0.001) = (1.00230524...)