4 ms·

Wait, what? The article mentions that the delta-v on the chart is required to go from the surface of Venus to a low Venusian orbit, not the other way around. I

Wait, what? The article mentions that the delta-v on the chart is required to go from the surface of Venus to a low Venusian orbit, not the other way around. I don't see why it would cost the same to go down from orbit to the surface. In fact, I'm pretty sure that a probe in a low Venusian orbit would decay on its own just like they do in low Earth orbit. I really don't see how going from a low Venusian orbit to the surface would be costly.

JumpCrisscross 7y ago
> The article mentions that the delta-v on the chart is required to go from the surface of Venus to a low Venusian orbit, not the other way around Delta-v is symmetrical. Putting something in orbit is mostly about accelerating tangentially to the surface, not about going up. Taking something out of orbit is mostly about accelerating tangentially to the surface, not about falling down. > I'm pretty sure that a probe in a low Venusian orbit would decay on its own just like they do in low Earth orbit Orbital decay for small objects is slow aerobraking. It is slow, requires a heat shield, and is structurally stressful.