>It means you get 1/4 the resistive loss (in the wires) for the same power. So you can pass 4 times the power over the same wires if you want. Wrong. P = VI an

>It means you get 1/4 the resistive loss (in the wires) for the same power. So you can pass 4 times the power over the same wires if you want. Wrong. P = VI and resistive losses are RI^2. For double voltage at the same power then yeah, R(I/2)^2 = 1/4 * RI^2. For double the voltage but 4 times the power then 4P = 2V(x*I) so x=2 and we square that so it's 4 times as much resistive losses. You can double the power if you double the voltage and keep the same resistive losses. The parent comment was right. >It means you get 1/4 the resistive loss (in the wires) for the same power. This is correct, but it scales with the square of the current, so you can't just extrapolate it linearly like that.