14 ms·
Commonwealth Fusion Systems was formed out of the work presented here: https://www.youtube.com/watch?v=KkpqA8yG9T4 https://www.youtube.com/watch?v=KkpqA8yG9T4
by maxharris 7y ago
Commonwealth Fusion Systems was formed out of the work presented here: https://www.youtube.com/watch?v=KkpqA8yG9T4 https://www.youtube.com/watch?v=KkpqA8yG9T4
A lot has changed since 1983. The superconducting materials that CFS depends on weren't even discovered until the late 80s, and it took a very long time for that to become practical. Fast-forward to today and you can buy this stuff on Alibaba!
- pfdietz 7y agoLidsky's arguments against fusion apply to the ARC design. Its overall volumetric power density is 0.5 MW/m^3, 40 times less than a PWR reactor vessel.
- pietjepuk88 7y agoWhat defines the volume to get to that number? From what I can tell from the ARC specs the plasma volume is 141 m3, and the expected power output is 200-300 MWe, which makes it 1.5-2 MWe/m3. Do you have some numbers on a PWR reactor vessel? I was trying to look up some details on the APR-1400, but could not find any.
- pfdietz 7y agoThe volume is the volume of the reactor, including blanket, magnets, and the structure needed to support the JxB forces on the magnets, not the volume of the plasma. See table 11, page 30, in the ARC paper: https://arxiv.org/pdf/1409.3540.pdf https://arxiv.org/pdf/1409.3540.pdf For PWRs: https://ocw.mit.edu/courses/nuclear-engineering/22-06-engineering-of-nuclear-systems-fall-2010/lectures-and-readings/MIT22_06F10_lec06a.pdf https://ocw.mit.edu/courses/nuclear-engineering/22-06-engine... (take the dimensions given for the primary reactor vessel, compute the volume as a cylinder with spherical end caps, and divide that into 3400 MW(th). The result is slightly below 20MW/m^3. Note also the power density of the core itself is given as greater than 100 MW/m^3.)