You know what, you're right. I made a knee-jerk comment but I didn't think it through all the way. From any arbitrary unsigned 32-bit integer, every other unsig

You know what, you're right. I made a knee-jerk comment but I didn't think it through all the way. From any arbitrary unsigned 32-bit integer, every other unsigned 32-bit integer is reachable with a single addition. Therefore addition works just fine here. It still feels wrong to say this, it feels like since adding will effectively shove bits off the high end and drop them on the floor that you're losing information, but I can't actually justify that feeling with reasoning.