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You don't bury the trees underground to store their carbon. You bury them in buildings. As lumber. Replace concrete (which produces CO2) in new buildings with
by mmaurizi 7y ago
You don't bury the trees underground to store their carbon.
You bury them in buildings. As lumber.
Replace concrete (which produces CO2) in new buildings with wood (which sequesters it) and you've tackled quite a bit of carbon emissions.
- nosianu 7y agoYou again look only at points in time or short periods and only at individual items instead of systems. Buildings are not a final permanent storage and they are not a different storage compared to trees, they basically serve the exact same purpose if you model global CO2 storage and have pretty much the same characteristics. Nothing changes by including buildings, you could just model it as a larger forest. Unless you add additional options by having two different items (tress + buildings), e.g. the option to stack them on top of one another, it does not matter if the carbon is stored in a tree or a building made from it. They all share the same limited surface space and you could just replace all buildings with trees in the model, or vice versa and it does not change the total storage capacity here on the surface. I refer back to everything I wrote.
- nosianu 7y agoYou again look only at points in time or short periods and only at individual items instead of systems. Buildings are not a final permanent storage and they are not a different storage compared to trees, they basically serve the exact same purpose if you model global CO2 storage and have pretty much the same characteristics. Nothing changes by including buildings, you could just model it as a larger forest. Unless you add additional options by having two different items (tress + buildings), e.g. the option to stack them on top of one another, it does not matter if the carbon is stored in a tree or a building made from it. They all share the same limited surface space and you could just replace all buildings with trees in the model, or vice versa and it does not change the total storage capacity here on the surface. I refer back to everything I wrote.