3 ms·
let projected = a.project(); let debugged = debug(projected); let ejected= debugged.eject();
by HelloNurse 7y ago
let projected = a.project();
let debugged = debug(projected);
let ejected= debugged.eject();
- heavenlyblue 7y agoAnd you need to change 3 lines in total (also you need to make changes mid-lines, too) in order to simply view the data in between, vs only 1 line. And by the way - if you paid attention in the first place my post actually has exactly what you've just written.
- HelloNurse 7y agoMeaningful names? I don't think so.
- heavenlyblue 7y agoAnd what is that meaning for if the functions you are calling have proper names?