4 ms·

sorted(u for u in users if u.last_name.startswith("S"), key=lambda u: u.last_name)[:3] Though I will conceed that I also find the fluent interface variant nice

sorted(u for u in users if u.last_name.startswith("S"), key=lambda u: u.last_name)[:3] Though I will conceed that I also find the fluent interface variant nicer.

mehrdadn 7y ago
That doesn't parse :-)