3 ms·
It is possible that the neutron emission number I found and used includes self shielding or is simply wrong. if the activity is 2.78e16 decays per second and no
by petschge 7y ago
It is possible that the neutron emission number I found and used includes self shielding or is simply wrong. if the activity is 2.78e16 decays per second and not just 1.1e15/s then the decay heat would be about 30kW.
But to be honest I am not sure if it is worthwhile to keep fixing bugs in this estimate. We know several good reason why there is no 1.4kg of Californium anywhere.
- russfink 7y agoI am awestruck at how smart people on this forum are. Many mod points for your calculations!