3 ms·
My mistake: We have (32*13) with minimal possible CHAR_BIT is 8. So it either 416 for char bigger then eight bits, or 160 for unsigned eight bits char, or -96 f
by m_kim 7y ago
My mistake: We have (32*13) with minimal possible CHAR_BIT is 8. So it either 416 for char bigger then eight bits, or 160 for unsigned eight bits char, or -96 for signed eight bits char. Then it extended to the signed integer value (one of this three values), and then we got result as (int)(status & 0377). For all three cases result will be 160.