A fiber will appear to be a thread. You can even call Thread.currentThread and get a consistent Thread object representing the fiber. This is done so that as mu

A fiber will appear to be a thread. You can even call Thread.currentThread and get a consistent Thread object representing the fiber. This is done so that as much existing code as possible would be able to run, unchanged, in fibers. We may (or may not), however, introduce newer, better constructs that new code will be encouraged to use.