5 ms·

How does extern void foo(char a[..]); differ from extern void foo(size_t dim, char a[dim]); if they are meant to be binary compatible?

• pjmlp 7y ago
  The programmer doesn't have to keep both in sync manually, so there is less chance that they blow up, as it happens regularly in C code, even after being reviewed.
  • inlined 7y ago
    I don’t recall that syntax being valid C. I thought the length modifier had to be a literal.
    • pjmlp 7y ago
      It doesn't matter, because it gets ignored anyway.