3 ms·
lol, what is a "strong function"? It is not the first time I hear physicist use this expression and I have no idea what it means.
by enriquto 7y ago
lol, what is a "strong function"? It is not the first time I hear physicist use this expression and I have no idea what it means.
- qwhelan 7y agoIt's asking whether Z dominates in terms of contribution to the result. AKA "Does knowing Z allow you to estimate the radius to first-order?"