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And why would you draw that distinction for unary operators but not binary ones? I wouldn't -- I think it's wrong for binary operators too.

• masklinn 16y ago
  Fair enough, but that most definitely isn't djacobs's case considering the replacement snippet he wrote.
  • sid0 16y ago
    I don't really want to speak for him, but what I got from his post was that he was saying that the unary syntax is as bad as C++'s (imho retarded) cout syntax.