3 ms·
Maybe there once was a breakpoint at the return false, or an assert, and it was just left like this in case the breakpoint is needed again.
by roel_v 7y ago
Maybe there once was a breakpoint at the return false, or an assert, and it was just left like this in case the breakpoint is needed again.
- indentit 7y agoModern debuggers generally support conditional breakpoints, but they often incur a high performance penalty, so this reasoning makes sense to me.