4 ms·
This was solved in rust by approaching it from the other side. You need to be explicit everywhere that a value is "borrowed", so while you never need a `->`, yo
by jkoudys 7y ago
This was solved in rust by approaching it from the other side. You need to be explicit everywhere that a value is "borrowed", so while you never need a `->`, you'll still know it's dereferencing in the more natural place - before the variable, not as an implied step after.