4 ms·
You could give every single IPv4 host its own complete IPv4 address space, and you would _still_ have enough addresses for 2 * 10^19 planets[1]. 2^128 is _absur
by stordoff 7y ago
You could give every single IPv4 host its own complete IPv4 address space, and you would _still_ have enough addresses for 2 * 10^19 planets[1]. 2^128 is _absurdly_ large.
[1] 2^128 / (2^32 * 2^32) = 1.84 * 10^19