4 ms·x = exp(-i)by jmpeax 7y agox = exp(-i)dangbang2 7y agoThe rhs is exp(ix), the numerator of the lhs is 2pi^2, and the lhs is some constant C. so the solution should look like x = i*log(C), not exp(-i)mnw21cam 7y agox = cos(1) - isin(1)