3 ms·
Indeed. But ld.so runs in the context of the process that is starting up, so if it doesn't have access to anything, it can't.
by mnw21cam 7y ago
Indeed. But ld.so runs in the context of the process that is starting up, so if it doesn't have access to anything, it can't.
- AstralStorm 7y agoIt doesn't actually have to, but you'd need a fun bit of stub code in place of unloaded function pointers etc.