4 ms·
AIUI, you don't need to "compute" sqrt5 to high precision in order to use that closed form! Just "adjoin" it to Q and compute symbolically over Q(sqrt5).
by 0815test 7y ago
AIUI, you don't need to "compute" sqrt5 to high precision in order to use that closed form! Just "adjoin" it to Q and compute symbolically over Q(sqrt5).
- lifthrasiir 7y agoThe computation over Q(sqrt(5)) is essentially identical to the matrix form.
- jacobolus 7y agoYes, and that symbolic computation is the same arithmetic as the original algorithm the author was complaining about. Personally I like the version better where you explicitly work in terms of integers like a + bφ or rational numbers like (a + bφ)/c. https://observablehq.com/@jrus/zome-arithmetic https://observablehq.com/@jrus/zome-arithmetic very handy when working with the symmetry system of the icosahedron. https://observablehq.com/d/cae3fea57d7cf2d4 https://observablehq.com/d/cae3fea57d7cf2d4
- irchans 7y agoNice. Thanks for that.