3 ms·> A ⊇ B, max(A) >= max(B) I think this is backwards - if A is a subset of B, max(A) <= max(B).by DuskStar 7y ago> A ⊇ B, max(A) >= max(B) I think this is backwards - if A is a subset of B, max(A) <= max(B).FabHK 7y agoThe special character might have not gone through well - I meant to say when A is a superset of B ("IU" rotated left 90 degrees).DuskStar 7y agoAnd I think I'm getting the superset/subset characters backwards. Sorry!