3 ms·

Sure, if A ⊇ B, max(A) >= max(B), but that does not imply that max(A\B) >= max(B).

• DuskStar 7y ago
  > A ⊇ B, max(A) >= max(B) I think this is backwards - if A is a subset of B, max(A) <= max(B).
  • FabHK 7y ago
    The special character might have not gone through well - I meant to say when A is a superset of B ("IU" rotated left 90 degrees).
    • DuskStar 7y ago
      And I think I'm getting the superset/subset characters backwards. Sorry!