3 ms·

.color(.gray)) What object is .gray acting on?

• didgeoridoo 7y ago
  That syntax is a shortcut for UIColor.gray, so this is really: .color(UIColor.gray)
  • JimDabell 7y ago
    I would expect it's the grey static member of SwiftUI's Color struct: https://developer.apple.com/documentation/swiftui/color/3049710-gray https://developer.apple.com/documentation/swiftui/color/3049...
• kennywinker 7y ago
  That’d be standard swift type inference. The .color function takes a single unnammed parameter of type Color (or similar, idk exactly). Color.gray is a static constant value. So .color(Color.gray) can be simplified to .color(.gray)
  • steve_adams_86 7y ago
    Huh, that's actually a great way to do type inference. Swift seems like an excellent language.
• deleted 7y ago
  [deleted]
• auggierose 7y ago
  that's shortcut syntax for an enumeration case where the type of the enumeration can be inferred
  • favorited 7y ago
    It's not just for enums. It works for any static variable on a given type. So you can say .gray and have it map to NSColor.gray, etc.
• kruuuder 7y ago
  I guess .color() is a method, and .gray is an enum case.
• deleted 7y ago
  [deleted]