5 ms·
When you begin with z = k i - 0.75, you can obtain an arbitrarily good approximation of pi by multiplying the p for which f_p(z) = z^2 + z diverges by k. The ap
by throwawaymath 7y ago
When you begin with z = k i - 0.75, you can obtain an arbitrarily good approximation of pi by multiplying the p for which f_p(z) = z^2 + z diverges by k. The approximation increases in precision as k tends to 0.
There's a neat video explaining it here: https://www.youtube.com/watch?v=d0vY0CKYhPY https://www.youtube.com/watch?v=d0vY0CKYhPY