3 ms·
> It seems very unlikely that 2 would occur because mining power approaches the brute force limits of SHA-256. Can you elaborate on this a bit more? I'm not fo
by lftl 7y ago
> It seems very unlikely that 2 would occur because mining power approaches the brute force limits of SHA-256.
Can you elaborate on this a bit more? I'm not following what you mean by the "mining power approaches the brute force limits of SHA-256."
- EthanHeilman 7y agoIf Bitcoin mining power continues to increase exponentially, it will eventually get to the point that it will brute force the output space of the SHA-256. This won't actually happen because 2^256 is a very^256 big number.