4 ms·
I'm confused how you could film a light pulse this way. It seems that the light pulse would itself have to be emitting light somehow. I'll assume it was travell
by davesque 7y ago
I'm confused how you could film a light pulse this way. It seems that the light pulse would itself have to be emitting light somehow. I'll assume it was travelling through a gas that scattered it.
- jerf 7y ago"The imaging system captures a light pulse (in a slowed video) as it passes through a material, exits the material (at the dashed yellow line) and bounces off a mirror (solid yellow line) back into the material."
- identicalgamer 7y agoIs this trying to imply that it is capturing the scattering off of the Frenel diffraction? I don't understand at first glance how this paper is capturing the light without having a sensor in the path of propagation.
- jerf 7y agoThe light is being put through a translucent medium, like shining a laser through milk or smoke or something, so you can see the scattered light. Conventional/non-QM-based light physics can handle this situation. If you mean, how are they seeing the non-scattered light, you are correct that they are not.
- HillaryBriss 7y ago> light is being put through a translucent medium at certain points, the light pulse seems to "leap ahead" in fits and starts on its journey. is that because of the way the medium scatters the light or something?
- mirimir 7y agoI think that it's because the speed of light inside the translucent medium (left side) is lower than in air (right side).
- deleted 7y ago[deleted]
- davesque 7y agoAh okay I get it. For some reason, I thought it was travelling through the material mentioned in that quote during the time it disappeared in the video.
- jcims 7y agoThe funny thing is that you can’t see the event in real time. You have to wait for the scattered light from the pulse to reach the camera sensor, kind of like the trailing sound from an airliner passing overhead, and by that time the actual pulse is out of frame.