4 ms·

Unrelated: thank you for using “idempotent” correctly. Too many people use it to mean referential transparency or having a functionality property

• globuous 7y ago
  wooow, so can we think of Black as outputing a projection of your source code in some space ?
  • thaumasiotes 7y ago
    Off the top of my head, sure, you could think of things that way, but I don't see that you get a lot out of that framing.
  • mlevental 7y ago
    wut? idempotent is any operator T such that T^2=e the identity. for example ring elements can be idempotent https://en.m.wikipedia.org/wiki/Idempotent_(ring_theory) https://en.m.wikipedia.org/wiki/Idempotent_(ring_theory). it's not just characteristic of linear operators.
    • CarlsJrMints 7y ago
      Idempotence means T^2=T. Are you thinking of involution? https://en.wikipedia.org/wiki/Involution_(mathematics) https://en.wikipedia.org/wiki/Involution_(mathematics)
      • mlevental 7y ago
        you're right i'm wrong. but my saving grace is that they're related https://en.wikipedia.org/wiki/Idempotent_(ring_theory)#Relation_with_involutions https://en.wikipedia.org/wiki/Idempotent_(ring_theory)#Relat...