As other comments have noted: varargs functions require at least one non-vararg parameter. (As int_19h said:) On some architectures, vararg functions have the

As other comments have noted: varargs functions require at least one non-vararg parameter. (As int_19h said:) On some architectures, vararg functions have their own distinct ABI, so (...) as a declaration is not compatible with any definition that doesn't also use (...).