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I would argue that lambda calculus without pervasive lazy evaluation is not lambda calculus. Lisps in general don’t have it (unlike Haskell) and make them not s
by cgrand-net 7y ago
I would argue that lambda calculus without pervasive lazy evaluation is not lambda calculus. Lisps in general don’t have it (unlike Haskell) and make them not so removed from hardware (once hardware stacks were added to CPUs). For long Lisps didn’t even have lexical closures!