8 ms·

Why do you say draining entropy is a fallacy? It is certainly true that entropy recorded from I/O sources accumulates at a very limited rate.

by dzdt 7y ago

deleted 7y ago
[deleted]
i80and 7y ago
There's no way to "use up" your entropy; this is a persistent myth that's been hanging around the Linux world for a very long time. * https://www.2uo.de/myths-about-urandom/#what-about-entropy-running-low https://www.2uo.de/myths-about-urandom/#what-about-entropy-r... * https://www.mail-archive.com/cryptography@randombit.net/msg04763.html https://www.mail-archive.com/cryptography@randombit.net/msg0...
deleted 7y ago
[deleted]
wolf550e 7y ago
Because after you gather ~256 bits of entropy from I/O sources (or rdrand^H^H^H rdseed [1]), using it to generate infinite output of /dev/urandom does not drain it. Adding more entropy only helps if the entropy pool inner state leaked, it is not needed to add more entropy because it drained through using it. Proof: 1. Take 256 bits of entropy. 2. Use HKDF to generate 128 bit key and 64 bit nonce. 3. Use key and nonce for AES-CTR with all possible 2^64 counter values to produce 2^68 bytes of output. 4. goto 2. If you can compute the inner state of the RNG (and thus predict future output) by just observing the output (not through side channels), using any amount of output, then all modern symmetric crypto is broken. If you can't, then using the entropy in an RNG does not drain the entropy pool. And here is a CCC talk about it: https://www.youtube.com/watch?v=OSfmtRc4VsE https://www.youtube.com/watch?v=OSfmtRc4VsE 1 - https://software.intel.com/en-us/blogs/2012/11/17/the-difference-between-rdrand-and-rdseed https://software.intel.com/en-us/blogs/2012/11/17/the-differ... EDIT: Thanks for 'dragontamer for pointing out difference between rdrand and rdseed.
- dragontamer 7y ago
  > If you can compute the inner state of the RNG (and thus predict future output) by just observing the output (not through side channels), using any amount of output, then all modern symmetric crypto is broken. If you can't, then using the entropy in an RNG does not drain the entropy pool. This seems wrong to me. If you can predict #1 (the 256-bits of entropy in step 1), then you can break the system. This is highly likely, as Intel only assures 65-bits of entropy across two rdrand calls. (64-bits of entropy from the first call, +1 bit from the 2nd call, since RDRAND is generated from an internal random number generator. So there's going to be a correlation between the two values). In effect, if #1 is created with four calls to RDRAND, you only have around 68-bits of entropy, which can be brute-forced faster than a true source of 256-bits of entropy. Therefore, your RNG is broken. https://software.intel.com/en-us/blogs/2012/11/17/the-difference-between-rdrand-and-rdseed https://software.intel.com/en-us/blogs/2012/11/17/the-differ... RDSEED is the instruction that guarantees 64-bits of independent / multiplicative entropy, but executes slower as a result. ---------- In effect, you're "simplifying" the problem. #1, getting 256 bits of entropy, is the hard part of the problem. You cannot ignore this part of the problem. In any case, it seems to me that a large number of people don't know how to properly use the RDRAND function, in this thread as well as in the Github thread. RDRAND has a chance of failure, AND it doesn't even hold multiplicative entropy guarantees. So this seems like a case of EVERYONE hasn't read the docs yet. Please people, do NOT use RDRAND as a source of entropy. Use RDSEED as a source of entropy. RDRAND is only a random number generator with only 64-bits of entropy guaranteed at any given state, and probably additive entropy at that.
  - wolf550e 7y ago
    I can ignore "how to do #1" when discussing whether entropy is drained by using it or not. You need to get 256 bits of high quality entropy. We assume there are ways to do that. On a device that has no way to do that, you can't do crypto (unless you accept the entropy from outside, which is key escrow, but might be ok for an IoT device that communicates only to its mothership).
    - dragontamer 7y ago
nwallin 7y ago
Which one of these statements is false: 1. When secure your TLS 1.2 connection with a 128 bit AES key, you can transmit a small amount of data (on the order of ~128 bits) before the entropy is drained from your CSPRNG state. 2. When you generate at least ~128 bits of entropy in your kernel's CSPRNG state, you can generate a very large amount of random bits before the entropy is drained from your CSPRNG state.

Why do you say draining entropy is a fallacy? It is certainly true that entropy recorded from I/O sources accumulates at a very limited rate.

by dzdt 7y ago

Why do you say draining entropy is a fallacy? It is certainly true that entropy recorded from I/O sources accumulates at a very limited rate.

deleted 7y ago

[deleted]

i80and 7y ago

There's no way to "use up" your entropy; this is a persistent myth that's been hanging around the Linux world for a very long time. * https://www.2uo.de/myths-about-urandom/#what-about-entropy-running-low https://www.2uo.de/myths-about-urandom/#what-about-entropy-r... * https://www.mail-archive.com/cryptography@randombit.net/msg04763.html https://www.mail-archive.com/cryptography@randombit.net/msg0...

deleted 7y ago

[deleted]

wolf550e 7y ago

Because after you gather ~256 bits of entropy from I/O sources (or rdrand^H^H^H rdseed [1]), using it to generate infinite output of /dev/urandom does not drain it. Adding more entropy only helps if the entropy pool inner state leaked, it is not needed to add more entropy because it drained through using it. Proof: 1. Take 256 bits of entropy. 2. Use HKDF to generate 128 bit key and 64 bit nonce. 3. Use key and nonce for AES-CTR with all possible 2^64 counter values to produce 2^68 bytes of output. 4. goto 2. If you can compute the inner state of the RNG (and thus predict future output) by just observing the output (not through side channels), using any amount of output, then all modern symmetric crypto is broken. If you can't, then using the entropy in an RNG does not drain the entropy pool. And here is a CCC talk about it: https://www.youtube.com/watch?v=OSfmtRc4VsE https://www.youtube.com/watch?v=OSfmtRc4VsE 1 - https://software.intel.com/en-us/blogs/2012/11/17/the-difference-between-rdrand-and-rdseed https://software.intel.com/en-us/blogs/2012/11/17/the-differ... EDIT: Thanks for 'dragontamer for pointing out difference between rdrand and rdseed.

dragontamer 7y ago
> If you can compute the inner state of the RNG (and thus predict future output) by just observing the output (not through side channels), using any amount of output, then all modern symmetric crypto is broken. If you can't, then using the entropy in an RNG does not drain the entropy pool. This seems wrong to me. If you can predict #1 (the 256-bits of entropy in step 1), then you can break the system. This is highly likely, as Intel only assures 65-bits of entropy across two rdrand calls. (64-bits of entropy from the first call, +1 bit from the 2nd call, since RDRAND is generated from an internal random number generator. So there's going to be a correlation between the two values). In effect, if #1 is created with four calls to RDRAND, you only have around 68-bits of entropy, which can be brute-forced faster than a true source of 256-bits of entropy. Therefore, your RNG is broken. https://software.intel.com/en-us/blogs/2012/11/17/the-difference-between-rdrand-and-rdseed https://software.intel.com/en-us/blogs/2012/11/17/the-differ... RDSEED is the instruction that guarantees 64-bits of independent / multiplicative entropy, but executes slower as a result. ---------- In effect, you're "simplifying" the problem. #1, getting 256 bits of entropy, is the hard part of the problem. You cannot ignore this part of the problem. In any case, it seems to me that a large number of people don't know how to properly use the RDRAND function, in this thread as well as in the Github thread. RDRAND has a chance of failure, AND it doesn't even hold multiplicative entropy guarantees. So this seems like a case of EVERYONE hasn't read the docs yet. Please people, do NOT use RDRAND as a source of entropy. Use RDSEED as a source of entropy. RDRAND is only a random number generator with only 64-bits of entropy guaranteed at any given state, and probably additive entropy at that.
- wolf550e 7y ago
  I can ignore "how to do #1" when discussing whether entropy is drained by using it or not. You need to get 256 bits of high quality entropy. We assume there are ways to do that. On a device that has no way to do that, you can't do crypto (unless you accept the entropy from outside, which is key escrow, but might be ok for an IoT device that communicates only to its mothership).
  - dragontamer 7y ago

nwallin 7y ago

Which one of these statements is false: 1. When secure your TLS 1.2 connection with a 128 bit AES key, you can transmit a small amount of data (on the order of ~128 bits) before the entropy is drained from your CSPRNG state. 2. When you generate at least ~128 bits of entropy in your kernel's CSPRNG state, you can generate a very large amount of random bits before the entropy is drained from your CSPRNG state.