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Obviously not? But there are trustworthy people working with and integrating that code, there's a good chance they'll notice a hinky commit, and they're very c
by phyzome 8y ago
Obviously not?
But there are trustworthy people working with and integrating that code, there's a good chance they'll notice a hinky commit, and they're very close to having completely reproducible builds—which means that there can be verification that the shipped binary matches the inspected source.
https://gregoryszorc.com/blog/2018/06/20/deterministic-firefox-builds/ https://gregoryszorc.com/blog/2018/06/20/deterministic-firef...