4 ms·
Is your horizon distance calculation based on no obstructions? Most people don't live on the plains ;) I am genuinely curious how you arrived at that number, F
by tnorthcutt 7y ago
Is your horizon distance calculation based on no obstructions? Most people don't live on the plains ;)
I am genuinely curious how you arrived at that number, FWIW – I don't know how to go about calculating something like that.
- petschge 7y agoThat does indeed assume a sphere. If you are curious about the geometry, maybe https://en.wikipedia.org/wiki/Horizon#Distance_to_the_horizon https://en.wikipedia.org/wiki/Horizon#Distance_to_the_horizo... can help. If you run the calculation the other way around, every satellite has to service a ground patch with about 380 miles radius. And your antenna has to swivel to a point that might be more than 60 degrees away from zenith. So every obstruction of more than 30 degrees above the horizon will lead to at least intermittent disconnects.