3 ms·
> it is not guaranteed that `memcmp(&i, &p, sizeof(p)) == 0`. Even less intuitively, it is not guaranteed that `(void*)i == p` since `i` is not an integer cons
by nybble41 8y ago
> it is not guaranteed that `memcmp(&i, &p, sizeof(p)) == 0`.
Even less intuitively, it is not guaranteed that `(void*)i == p` since `i` is not an integer constant expression, even if the value is known to be 0.