3 ms·
It does make sense in a mathematical context though. You might write something like p_S = \prod_{x \in S} x And then later find out that the set S contains on
by Certhas 8y ago
It does make sense in a mathematical context though. You might write something like
p_S = \prod_{x \in S} x
And then later find out that the set S contains one element. Or it might even be the empty set in which case you'd interpret the above as equal to 1. This makes it work that
p_{S union S'} = p_S p_S'
in all cases.
- rocqua 8y agoYou either need a disjoint union there (or equivalently multi-sets) or the assumption that S and S' are disjoint.