3 ms·
It's a little better than that: 1.57^52 - 1. R_n = (1 + R_0)(1 + R_1)...(1 + R_n) - 1 It's easier to just use log return: r_n = r_0 + r_1 ... r_n where r =
by mruts 8y ago
It's a little better than that: 1.57^52 - 1.
R_n = (1 + R_0)(1 + R_1)...(1 + R_n) - 1
It's easier to just use log return:
r_n = r_0 + r_1 ... r_n
where
r = log (1 + R)
Anyhow, compounded returns aren't the best way to think about this. It's not like they could extend the period and realize the compounded returns.