2 ms·
No, outside observer will measure clocks of photon run slower by a factor of γ (Lorentz factor), which (in scalar form) is equal to 1/sqrt(1 - v^2 / c^2 ). It d
by Yajirobe 8y ago
No, outside observer will measure clocks of photon run slower by a factor of γ (Lorentz factor), which (in scalar form) is equal to 1/sqrt(1 - v^2 / c^2 ). It diverges at v = c.
- pdonis 8y ago> outside observer will measure clocks of photon run slower by a factor of γ This is not correct since "clocks of photon" is a meaningless concept (at least if photons have zero mass, which they do according to our best current models).
- Yajirobe 8y agoObviously, I did not mean to imply that you can attach a clock on a photon. I thought this goes without saying.
- pdonis 8y ago> I did not mean to imply that you can attach a clock on a photon. The issue isn't that you can't attach a clock to a photon in a practical sense. The issue is that even in principle, the concept of "the clock of a photon" is not well-defined. For it to be well-defined, there would need to be an inertial frame in which a photon was at rest. But that is impossible.