5 ms·

It's the color scheme. I think in matplotlib it's called "hot". I do a lot of 2D kernel density plots that by having a black zero level and dozens of contour le

It's the color scheme. I think in matplotlib it's called "hot". I do a lot of 2D kernel density plots that by having a black zero level and dozens of contour levels produce a smooth look with aesthetics similarities to this. I used to use that scheme because "heatmaps" but stopped because of the pulsing illusion. I'm not sure if this image is real color or just lightness value and they used a color scheme for drama.

317070 8y ago
It's the latter. This is an image in radio-frequency brightness of the object, so not visible frequencies of light. But yeah, it also looks like the 'hot' colormap to me.
Mizza 8y ago
Grrr, why aren't scientists all using perceptually uniforms color schemes! This would still look awesome in `plasma`. Is there any where I can get the data and do it myself? One of my favorite talks ever is on this subject: https://www.youtube.com/watch?v=xAoljeRJ3lU https://www.youtube.com/watch?v=xAoljeRJ3lU
- kardos 8y ago
  Can you run it through the colormap in reverse to (approximately) recover the data?
  - yehar 8y ago
    Based on my analysis the published image is too processed to be able to invert the colormap to get to the brightness temperature data. I had better luck with Paper IV Fig. 15. See: https://physics.stackexchange.com/questions/472641/what-would-the-event-horizon-telescope-m87-black-hole-image-look-like-if-we-saw https://physics.stackexchange.com/questions/472641/what-woul...
  - thanatropism 8y ago
    Technically yes -- colormaps are 1-dimensional non-self intersecting curves in RGBA space. You just grab them by the... I mean just straighten them. I don't know if an explicit formula for the colormap is given, but you can always do "xs = np.linspace(0,1,100); ys = { cm.hot(x):x for x in xs}" and recover an approximate inverse. Then apply this function to each pixel of the image.
- Osmium 8y ago
  'Inferno' would be nice for this, also perceptually uniform, and has the benefit that space is still black.
- knolan 8y ago
  You can easily remap it between different colour maps if you assume that is is a standard hot map.

317070 8y ago

It's the latter. This is an image in radio-frequency brightness of the object, so not visible frequencies of light. But yeah, it also looks like the 'hot' colormap to me.

Mizza 8y ago

Grrr, why aren't scientists all using perceptually uniforms color schemes! This would still look awesome in `plasma`. Is there any where I can get the data and do it myself? One of my favorite talks ever is on this subject: https://www.youtube.com/watch?v=xAoljeRJ3lU https://www.youtube.com/watch?v=xAoljeRJ3lU

kardos 8y ago
Can you run it through the colormap in reverse to (approximately) recover the data?
- yehar 8y ago
  Based on my analysis the published image is too processed to be able to invert the colormap to get to the brightness temperature data. I had better luck with Paper IV Fig. 15. See: https://physics.stackexchange.com/questions/472641/what-would-the-event-horizon-telescope-m87-black-hole-image-look-like-if-we-saw https://physics.stackexchange.com/questions/472641/what-woul...
- thanatropism 8y ago
  Technically yes -- colormaps are 1-dimensional non-self intersecting curves in RGBA space. You just grab them by the... I mean just straighten them. I don't know if an explicit formula for the colormap is given, but you can always do "xs = np.linspace(0,1,100); ys = { cm.hot(x):x for x in xs}" and recover an approximate inverse. Then apply this function to each pixel of the image.
Osmium 8y ago
'Inferno' would be nice for this, also perceptually uniform, and has the benefit that space is still black.
knolan 8y ago
You can easily remap it between different colour maps if you assume that is is a standard hot map.