3 ms·
It's trying to divide "Illegal division by zero at /" by "tmp/quine.pl line 1." and "tmp/quine.pl line 1." evaluates to 0?
by 275qaz 8y ago
It's trying to divide "Illegal division by zero at /" by "tmp/quine.pl line 1." and "tmp/quine.pl line 1." evaluates to 0?
- benj111 8y agoOr "quine.pl line 1." Evaluates to 0? Or should that be 0.0???
- yellowapple 8y agoYeah, I think it's both divisions. Both 'perl -e "in /tmp"' and 'perl -e "tmp/quine"' result in the same division-by-zero error.
- barthold 8y agoI think it's equivalent to something like Illegal::division(by::zero(at/tmp/quine . pl::line(1.)))
- fanf2 8y agoIt is slightly more complicated than that :-) https://fanf.dreamwidth.org/131318.html https://fanf.dreamwidth.org/131318.html the actual parse is division->Illegal( zero->by( ((“at” / “tmp”) / “quine”) . line->pl(1.0) ))