4 ms·
You can get five with (1/3 + 1/3 + 1/3 + 1/3 - 1/3). Note that I'm not really talking about charges directly so they don't need to be equal, but rather I'm usin
by Retra 8y ago
You can get five with (1/3 + 1/3 + 1/3 + 1/3 - 1/3). Note that I'm not really talking about charges directly so they don't need to be equal, but rather I'm using these numbers as a proxy for charges. So this configuration might be something like (red, green, blue, red, antired).
It's just a quick rule for showing how many quarks can fit together, not what kinds of quarks they are.
- JadeNB 8y ago> You can get five with (1/3 + 1/3 + 1/3 + 1/3 - 1/3). I'm sorry; although you very clearly referred to winding up with a whole number, I somehow read it as winding up with 0.