2 ms·
To be honest, this is false too. You need functions with values that can be multiplied by scalars. If you just have ordered set, then you can't account for this
by enedil 8y ago
To be honest, this is false too. You need functions with values that can be multiplied by scalars. If you just have ordered set, then you can't account for this constant from the definition. Alternatively, you could say that values of the function need to be from a normed vector space (but I'm not sure if it can be extended furthermore. Maybe normed C-module?)
- umanwizard 8y agoSure, but that doesn't change my point.