> Why does a path in D-Bus need to have a 32-bit length? Is 16 (64K) or even 8 (255) bits sufficient? I'm not sure what path is in this context but if I assume

> Why does a path in D-Bus need to have a 32-bit length? Is 16 (64K) or even 8 (255) bits sufficient? I'm not sure what path is in this context but if I assume file path (the rest of my post will look stupid if it's not) then 16 seems more than enough, but 8 has bitten many people in the windows world before. I'm also unsure of the context, is it always a path or is it a generic message that will be a path in this context? If it's the latter then there are many instances where 32-bit makes sense and then regardless of what is suitable for a path the 32-bit length is the contract.