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The minimal herbrandt model does not have new atoms. Besides what is given in the rules and the starting facts (empty for least fix point). So the "biggest" mo
by maweki 8y ago
The minimal herbrandt model does not have new atoms. Besides what is given in the rules and the starting facts (empty for least fix point).
So the "biggest" model is only as large as any atom in any position for any predicate and that is always finite for a finite number of sorts or predicates.
Is gave is/2 as an example of how Prologo allows you to generate new atoms/terms that have not been facts before.
- YeGoblynQueenne 8y agoApologies- I misunderstood your example with is/2.